Решите плз не а б с а решить надо плиз

$\frac{2\frac{5}{8}-2\frac{5}{14}\cdot\frac{2}{3}}{(3\frac{1}{12}+4,375):19\frac{8}{9}}=2\frac{17}{21} \\ 1) 2\frac{5}{8}-2\frac{5}{14}\cdot\frac{2}{3}=\frac{5}{8}-\frac{33}{14}\cdot\frac{2}{3}=2\frac{5}{8}-\frac{11}{7}=2\frac{5}{8}-1\frac{4}{7}=1+\frac{35-32}{56}= \\ =1\frac{3}{56}, \\$

$2) 3\frac{1}{12}+4,375=3\frac{1}{12}+4\frac{3}{8}=7+\frac{2+9}{24}=7\frac{11}{24}, \\ 3) 7\frac{11}{24}:19\frac{8}{9}=\frac{179}{24}:\frac{179}{9}=\frac{179}{24}:\frac{179}{9}=\frac{179}{24}\cdot\frac{9}{179}=\frac{3}{8}, \\ 4) \frac{1\frac{3}{56}}{\frac{3}{8}}=\frac{59\cdot8}{56\cdot3}=\frac{59}{21}=2\frac{17}{21}.$