1)0,5(3x-8)/[0,5(x²-2x+4)]-0,5(4x-28)/[0,5(x+2)(x²-2x+4)]+1/(x+2)=
=(3x-8)/(x²-2x+4)-(4x-28)/[(x+2)(x²-2x+4)]+1/(x+2)=
=(3x²+6x-8x-16-4x+28+x²-2x+4)/[(x+2)(x²-2x+4)]=
=(4x²-8x+16)/[(x+2)(x²-2x+4)=4(x²-2x+4)/[(x+2)(x²-2x+4)]=4/(x+2)
2)4/(x+2)*(x+2)/4=1