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Решите задачу:

$2 \frac{5}{9} + 5 \frac{8}{9} = 7 \frac{5+8}{9} = 7 \frac{13}{9} = 8 \frac{4}{9}$

$5 \frac{2}{5} - 2 \frac{2}{15} = 3 \frac{6-2}{15} = 3 \frac{4}{15}$

$1 \frac{5}{12} - \frac{9}{20} = 1 \frac{25-27}{60} = \frac{58}{60} = \frac{29}{30}$

$1 \frac{13}{18} + \frac{1}{4} = 1 \frac{26+9}{36} = 1 \frac{35}{36}$

$1 + \frac{7}{8} = 1 \frac{7}{8}$

$5 \frac{7}{18} + 4 \frac{7}{9} = 9 \frac{7+14}{18} = 9 \frac{21}{18} = 10 \frac{3}{18} = 10 \frac{1}{6}$

$3 \frac{7}{13} - 2 \frac{7}{13} = 1$

$2 - \frac{8}{19} = 1 \frac{19-8}{19} = 1 \frac{11}{19}$

$1 \frac{6}{13} + 3 \frac{5}{8} = 4 \frac{48+65}{104} = 4 \frac{113}{104} = 5 \frac{9}{104}$

$3 \frac{5}{21} + \frac{5}{6} = 3 \frac{10+35}{42} = 3 \frac{45}{42} = 3 \frac{3}{42} = 3 \frac{1}{14}$

$5 \frac{11}{18} - \frac{11}{14} = 5 \frac{77-99}{126} = 4 \frac{104}{126} = 4 \frac{52}{63}$

$4 \frac{5}{6} + 1 \frac{1}{18} = 5 \frac{15+1}{18} = 5 \frac{16}{18} = 5 \frac{8}{9}$

$1 - \frac{6}{7} = \frac{1}{7}$

$1 \frac{16}{17} - 1 \frac{9}{17} = \frac{7}{17}$

$4 \frac{8}{15} + 2 \frac{7}{15} = 6 \frac{15}{15} = 7$

$3 \frac{2}{9} - 1 = 2 \frac{2}{9}$

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