Решите задачу:
K≥4k≥4 k!k! : 2m2m m>k/2m>k/2 2nk−1−32nk−1−3 n>2k/2n>2k/2 2nk−3n>nk>2k2/2>k!.2nk−3n>nk>2k2/2>k! k<4k<4</strong>.