даю 30 балов пж
1/(n+1) - 1/(n-6) =7/12 /.12(n+1)(n-6), n≠-1, n≠6 12(n-6)-12(n+1)=7(n+1)(n-6) 12n-72-12n-12=7(n²-6n+n-6) -84=7n²-35n-42 7n²-35n-42+84=0 7n²-35n+42=0 /:7 n²-5n+6=0 (n-2)(n-3)=0 a)n-2=0, n=2 b)n-3=0,n=3