Решите уравнение :(2 2/3x +1 3/7x)*21=58
2 2/3*Х? ИЛИ 3Х В ЗНАМЕНАТЕЛЕ ДРОБИ?
( 2 2/3х + 1 3/7х ) • 21 = 58 2 2/3 + 1 3/7 = 2 14/21 + 1 9/21 = 3 23/21 = 4 2/21 ( 4 2/21 )Х • 21 = 58 ( 86/21 )Х = 58/21 86х = 58 Х = 58/86 Х = 29/43
(2 2/3*х+1 3/7*х)*21=58 (2 14/21*х+1 9/21*х)*21=58 3 23/21*х*21=58 4 2/21*х*21=58 4 2/21*х=58:21 4 2/21*х=58/21 х=58/21:86/21 х=58/86 х=29/43