Помоги пожалуйста, срочно.

1) $(9 \frac{1}{4}*8) - (1 \frac{2}{3} *5 \frac{1}{2} ) - (2 \frac{4}{5} *2 \frac{11}{12})$ = $( \frac{37*8}{4}) - ( \frac{5*11}{3*2}) - ( \frac{14*35}{5*12})$ = $(37*2) - \frac{55}{6} - \frac{49}{6} = \frac{444-55-49}{6} = \frac{340}{6} = 57 \frac{4}{6} = 57 \frac{2}{3}$
2) $(1 \frac{1}{22} *3 \frac{2}{3}) - (2 \frac{5}{6} + 3 \frac{5}{6} * \frac{7}{23} )* \frac{3}{5} = ( \frac{23*11}{22*3}) - (2 \frac{5}{6} + \frac{23*7}{6*23})* \frac{3}{5}$ = $\frac{23}{6} - ( \frac{17+7}{6})* \frac{3}{5} = \frac{23}{6} - (4*\frac{3}{5}) = \frac{23}{6} - \frac{12}{5} = \frac{(5*23)-(12*6)}{30} = \frac{115-72}{30} = \frac{43}{30}$ = $1 \frac{13}{30}$