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Question

(х-y)+(2y-3b);-(а-b)+(-x+a)-(b-x);-(х-9)+(а-5);(а-7)-(5+а)-(9-а);(х-а)+(y+b);-(m+n)+(n-p)-(-p-m);(-m+8)-(m-4)+(-8+m);(b-4)-(-c+7)

Answer 1

(х-y)+(2y-3b)= х-у+2y-3b

-(а-b)+(-x+a)-(b-x)= -а+b-x+a-b+x=0

-(х-9)+(а-5)= -х+9+а-5=-х+а+4

(а-7)-(5+а)-(9-а)= а-7-5-а-9+а=а-21

(х-а)+(y+b)= х-а+y+b

-(m+n)+(n-p)-(-p-m)= -m-n+n-p+p+m=0

(-m+8)-(m-4)+(-8+m)= -m+8-m+4-8+m=4-m

(b-4)-(-c+7)= b-4+c-7= b+c-11