А). (√3-√2)/(⁴√3+⁴√2)=(
(⁴√3-⁴√2)·(⁴√3+⁴√2)/
(⁴√3+⁴√2)=
⁴√3-⁴√2
б) .19 19- (∛100-∛90+∛81)·(
∛10 +∛9)
---------------------- -∛10 -∛9 = ------------------------------------------- =
∛100-∛90+∛81 ∛100-∛90+∛81
19- (∛1000-∛900+∛810+∛900-∛810+∛729) 19-10-9
--------------------------------------------------------- = ------------------= 0
∛100-∛90+∛81 ∛100-∛90+∛81