Решите неравенство (x+2)(3x-2)(3x-1)=>0
(x+2)(3x-2)(3x-1)≥0 (x+2)*3(x- ²/₃)*3(x- ¹/₃)≥0 (x+2)(x- ²/₃)(x- ¹/₃)≥0 x= -2 x= ²/₃ x=¹/₃ - + - + --------- -2 --------- 1/3 ------------ 2/3 ------------ \\\\\\\\\\\\ \\\\\\\\\\\\\\ x∈[-2; 1/3]U[2/3; +∞) Ответ: [-2; 1/3]U[2/3; +∞)