(X+1)(x+2)-(x+3)(x+4)=0

Question

(X+1)(x+2)-(x+3)(x+4)=0

Comments

х^2+2x+x+2-x^2-4x-3x-12=0 -4x-10=0 -4x=10 x=10/(-4) x=-2.5

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х^2+2x+x+2-x^2-4x-3x-12=0 ; -4x-10=0 ; -4x=10 ; x=10/(-4) ; x=-2.5

Answer 1

Решите задачу:

Answer 2

X^2+2x+x+2- x^2+4x+3x+12=0
-4x=10
x=10: (-4)
x=-2.5