] 3+\sqrt{6}\\ 7+2\sqrt{7*8}+8>9+6\sqrt{6}+6\\ 2\sqrt{56}>\sqrt{6}\\ 4*56>6 " alt="\sqrt{7}+\sqrt{8}>3+\sqrt{6}\\ 7+2\sqrt{7*8}+8>9+6\sqrt{6}+6\\ 2\sqrt{56}>\sqrt{6}\\ 4*56>6 " align="absmiddle" class="latex-formula">
4*56>6 - верно.
Значит:
3+\sqrt{6}\\" alt="\sqrt{7}+\sqrt{8}>3+\sqrt{6}\\" align="absmiddle" class="latex-formula">