А) 5/6b+3/10b-7/15b;Б)3целых5/6y-2целых5/12y+1 целая1/3y

Решите задачу:

$\frac{5}{6}b+ \frac{3}{10} b - \frac{7}{15} b = ( \frac{5}{6} + \frac{3}{10} + \frac{7}{15} )*b = \frac{50 + 18 + 28}{60} b = \\ \\= \frac{96}{60}b = \frac{8}{5} b = 1 \frac{3}{5}b=1.6b \\ \\$

$3 \frac{5}{6} y - 2 \frac{5}{12} y+ 1 \frac{1}{3}y= ( 3 \frac{5}{6} - 2 \frac{5}{12} + 1 \frac{1}{3})*y= \\ \\ =(3 \frac{10}{12} - 2 \frac{5}{12} + 1 \frac{4}{12})*y= 2 \frac{9}{12} y = 2 \frac{3}{4} y= 2.75y$