Сократите
[(x²+2xy+y²)-c(x+y)]/[x(y+c)+(y-c)(y+c)]=[(x+y)²-c(x+y)]/[(y+c)(x+y-c)]= =(x+y)(x+y-c)//[(y+c)(x+y-c)]=(x+y)/(y+c)