Решить: а)(42/5 – 32/7)·5; б)85/11·4 2/9 + 8 5/11·6 7/9; в)(2 – 1 8/15)·30. Кто решит...

Решите задачу:

$( \frac{42}{5}- \frac{32}{7})*5=( \frac{4 2^{|7}}{5}- \frac{3 2^{|5} }{7})*5=( \frac{294-160}{35})*5= \frac{134}{35}*5= \frac{134}{7}=19 \frac{1}{7} \\ \\ 8 \frac{5}{11} *4 \frac{2}{9}+8 \frac{5}{11}*6 \frac{7}{9}= \frac{93}{11}* \frac{38}{9}+ \frac{93}{11}* \frac{61}{9}= \frac{3534+5673}{99}= \frac{9207}{99}=93 \\ \\ (2-1 \frac{8}{15})*30=( \frac{30}{15}- \frac{23}{15})*30= \frac{7}{15}*30=14$