решите неравенство:log2(x-3)>=2
0, \\ x-3\geq2^2, \\ x-3\geq4, \\ x\geq7, \\ x\in[7;+\infty)" alt="\log_2(x-3)\geq2, \\ x-3>0, \\ x-3\geq2^2, \\ x-3\geq4, \\ x\geq7, \\ x\in[7;+\infty)" align="absmiddle" class="latex-formula">
0, \\ x-3\geq2^2, \\ x-3\geq4, \\ x\geq7, \\ x\in[7;+\infty)" alt="\log_2(x-3)\geq2, \\ x-3>0, \\ x-3\geq2^2, \\ x-3\geq4, \\ x\geq7, \\ x\in[7;+\infty)" align="absmiddle" class="latex-formula">