система уравнений
(2х–3у)(2х+3у)=12 2х–3у=3; 3(2х+3у)=12 2х–3у=3; 2х+3у=4 2х–3у=3; 2х=4–3у (4–3у)–3у=3; 2х=4–3у 4–6у=3; 2х=4–3у 6у=1; 2х=4–3у у=1/6; 2х=4–3*1/6 у=1/6; 2х== 4–1/2 у =1/6; 2х=7/2 у=1/6; х =7/4 у =1/6.
{4x^2 - 9y^2 = 12 {(2x - 3y)(2x + 3y) = 12 3(2x + 3y) = 12 2x + 3y = 4 {2x - 3y = 3 {2x + 3y = 4 Решим систему методом сложения {2x - 3y = 3 4х = 7 х = 7/4 х = 1,75 2*1,75 + 3у = 4 3у = 4 - 1,5 3у = 2,5 у = 2,5/3 у = 5/6 Ответ. (1,75; 5/6)