-x^2+5x(дробная черта) 1-6x + 41x^2-2x(дробная черта) 6x-1 Помогите, срочно, в алгебре 0 ( полное решение без решебника!)
Solve for x over the real numbers: -(x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0 Multiply both sides by -1: (x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0 Multiply both sides by (6 x-1) (41 x^2-8 x+1): x (x-5) = 0 Split into two equations: x-5 = 0 or x = 0 Add 5 to both sides: Answer: x = 5 or x = 0