(2+i)(3-i) (5+6i)(-2+3i)

Question

(2+i)(3-i)


(5+6i)(-2+3i)

Answer 1

(2+i)(3-i) = 6 + 3i -2i -i*i = 6 + i + 1= 7 + i
(5+6i)(-2+3i)=-10+15i+18i*i-12i= -10 +3i -18 = 3i -28