3^(4x+3)<(1/9)^(x^2/2)
3^(4x+3)<3^(-x^2/2)</p>
4x+3<-x^2/2</p>
x²/2+4x+3<0</p>
x²+8x+6<0</p>
D=8²-4*1*6=64-24=40
x1=-4-√10
x2=-4+√10
x∈(-4-√10;-4+√10)