![|x+4|=|x-4|
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\left \{ {{x+4=x-4} \atop {x+4=4-x}} \right.
\\\
\left \{ {{4 \neq -4} \atop {2x=0}} \right.
\\\
x=0](https://tex.z-dn.net/?f=%7Cx%2B4%7C%3D%7Cx-4%7C%0A%5C%5C%5C%0A+%5Cleft+%5C%7B+%7B%7Bx%2B4%3Dx-4%7D+%5Catop+%7Bx%2B4%3D4-x%7D%7D+%5Cright.+%0A%5C%5C%5C%0A+%5Cleft+%5C%7B+%7B%7B4+%5Cneq+-4%7D+%5Catop+%7B2x%3D0%7D%7D+%5Cright.+%0A%5C%5C%5C%0Ax%3D0 "|x+4|=|x-4|
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\left \{ {{x+4=x-4} \atop {x+4=4-x}} \right.
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\left \{ {{4 \neq -4} \atop {2x=0}} \right.
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x=0")
Ответ: 0
x^2 -5x+6
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\left \{ {{x^2 -5x+6> x^2 -5x+6} \atop {x^2 -5x+6<- x^2 +5x-6}} \right.
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\left \{ {{0>0} \atop {2x^2 -10x+12<0}} \right.
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x^2 -5x+6<0
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D=25-24=1
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x_1= \frac{5+1}{2}=3
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x_2= \frac{5-1}{2}=2
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x\in (2;3)" alt="|x^2 -5x+6|> x^2 -5x+6
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\left \{ {{x^2 -5x+6> x^2 -5x+6} \atop {x^2 -5x+6<- x^2 +5x-6}} \right.
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\left \{ {{0>0} \atop {2x^2 -10x+12<0}} \right.
\\\
x^2 -5x+6<0
\\\
D=25-24=1
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x_1= \frac{5+1}{2}=3
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x_2= \frac{5-1}{2}=2
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x\in (2;3)" align="absmiddle" class="latex-formula">
Ответ: 2