Log_1/3 (7x-4x^2)=-1

Question

Log_1/3 (7x-4x^2)=-1

Answer 1

㏒₁₎₃ (7х-4х²)= -1
        
7х-4х²=(1/3)⁻¹

7х-4х²=3

4х²-7х+3=0

D=49-48=1

х₁=(7+1)/8=1

х₂=(7-1)/8=6/8=3/4