Log1/3(3x+5)>log1/3(x^2+1)

Question

Log1/3(3x+5)>log1/3(x^2+1)

Answer 1

Т к 1/3<1, то 3х+5<х²+1<br>х²-3х-4>0
D=9+16=25
x=(3+5)/2=4
x=(3-5)/2=-1
x∈(-∞;-1)∪(4;+∞)
ОДЗ 3х+5>0
x>-5/3⇒x∈(-5/3;-1)∪(4;+∞)