(5x+2)(-x-4)=0 плиззз срочно,!!!....

(5x+2)(-x-4)=0

-5х^2 - 20x -2x-8=0

-5х^2 - 22x - 8=0

$x_{1,2} = \frac{-(-22)+/- \sqrt{22^{2}-4*(-5)*(-8) } }{2*(-5)}= \frac{22+/- \sqrt{484-160} }{-10} = \frac{22+/- \sqrt{324} }{-10}$ = $\frac{22+/-18}{-10}$

x_{2} = \frac{22-18}{-10} = \frac{4}{-10} = -0.4 " alt=" x_{1} = \frac{22+18}{-10} = \frac{40}{-10} = -4

x_{2} = \frac{22-18}{-10} = \frac{4}{-10} = -0.4 " align="absmiddle" class="latex-formula">

Ответ: х1=-4; х2=-0,4