3а-3в-с•(а-в)а^4-а^3-4а+425в^2-(5-в)^2

Question

3а-3в-с•(а-в)
а^4-а^3-4а+4
25в^2-(5-в)^2

Answer 1

3a-3b-c*(a-b)=3*(a-b)-c*(a-b)=(3-c)*(a-b)
а^4-а^3-4а+4=а^3*(a-1)-4*(a-1)=(а^3-4)*(a-1)

Comments

А 3?))

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Не успела. :(