ОДЗ : 
4\ \ |\frac{\sqrt{x}+1}{\sqrt{x}-2}|=\frac{\sqrt{x}+1}{\sqrt{x}-2}\\\\" alt="1)\ \Pi pu\ 0 \leq x<4\ \ |\frac{\sqrt{x}+1}{\sqrt{x}-2}|=-\frac{\sqrt{x}+1}{\sqrt{x}-2}=\frac{\sqrt{x}+1}{2-\sqrt{x}}\\\\
2)\ \Pi pu\ x>4\ \ |\frac{\sqrt{x}+1}{\sqrt{x}-2}|=\frac{\sqrt{x}+1}{\sqrt{x}-2}\\\\" align="absmiddle" class="latex-formula">