Решите неравенство: 1) 2^x < 1/2 2) (1/3)^x > 1/27 3) (2/3)^(3x+6) > 4/9

Question

Решите неравенство:
1) 2^x < 1/2
2) (1/3)^x > 1/27
3) (2/3)^(3x+6) > 4/9

Answer 1

1)2^х <1/2<br>2^х+1 <1<br>х+1 <0<br>х <-1<br>2) 1/3^х>1\27
1/3^х-3>1
х-3 <0<br>х <3<br>3)2/3^3х+6>4/9
2/3^3х+6-2>1
3х+4>0
3х>-4
х>-4/3