(y-2)(y+3)-(y-2)<6y-11

Question

(y-2)(y+3)-(y-2)<6y-11

Comments

Решите пж

Answer 1

У^2 + у - 6 - у + 2 < 6у - 11
у^2 - 6у - 4 + 11 < 0
у^2 - 6у + 7 < 0
D/4 = 9 - 7 = 2
у1 = 3 + √2
у2 = 3 - √2
(у-3-√2)×(у-3+√2)<0<br>у € (3-√2 ; 3+√2)

Answer 2

Y^2+3y-2y-6-y+2<6y-11<br>y^2-4<6y-11<br>y^2+6y-4+11<0<br>y^2+6y+7=0
D=36+4*2*7