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0
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D=9-8=1
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x_1= \frac{3+1}{2} =2
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x_2= \frac{3-1}{2} =1
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x\in(-\infty; 1]\cup[2; +\infty)" alt="- x^{2} +3x-2<0
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x^{2} -3x+2>0
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D=9-8=1
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x_1= \frac{3+1}{2} =2
\\\
x_2= \frac{3-1}{2} =1
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x\in(-\infty; 1]\cup[2; +\infty)" align="absmiddle" class="latex-formula">