(log6 3+log3 1296+4) (log6 3-log108 9) log3 6-log6 3

Question

(log6 3+log3 1296+4) (log6 3-log108 9) log3 6-log6 3

Answer 1

Перейдем к основанию 6
(log(6)3+4/log(6)3 + 4)*(log(6)3-2log(6)3/(2+log(6)3) *1/log(6)3 - log(6)3=2
Обозначим log(6)3=a
(a+4/a+4)(a-2a/(a+2)*1/a -a=(a²+4+4a)/a * (a²+2a-2a)/(a+2)*1/a - a=
=(a+2)²/a *a²/(a+2)*1/a -a=a+2-a=2