b_1=\dfrac{b_4}{q^3}=\dfrac{24}{(-2)^3}=\dfrac{24}{-8}=-3\\
S_6=\dfrac{b_1(q^6-1)}{q-1}=\dfrac{-3((-2)^6-1)}{-2-1}=\dfrac{-3*63}{-3}=63" alt="b_4=24,\ q=-2\ => b_1=\dfrac{b_4}{q^3}=\dfrac{24}{(-2)^3}=\dfrac{24}{-8}=-3\\
S_6=\dfrac{b_1(q^6-1)}{q-1}=\dfrac{-3((-2)^6-1)}{-2-1}=\dfrac{-3*63}{-3}=63" align="absmiddle" class="latex-formula">
Ответ: 63