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[(sinα+cosα)²-1]/(tgα-sinα·cosα) -2/(sin²(π+α))= =(sin²α+2sinα·cosα+cos²α-1)/(sinα/cosα-sinα·cosα) -2/(sin²α)= =(2sinα·cosα)/[sinα(1-cos²α)/cosα] -2/(sin²α)=2[cos²α/sin²α]-2/(sin²α)= =2[(cos²α-1)/sin²α]=2sin²α/sin²α=2