Корень из(25-x^2) больше 4

$\sqrt{25- x^{2} } \ \textgreater \ 4$
$\left \{ {{25- x^{2} } \geq 0} \atop {( \sqrt{25- x^{2} })^2 \ \textgreater \ 4^2}} \right.$
$\left \{ {{(5-x)(5+x) } \geq 0} \atop {25- x^{2} \ \textgreater \ 16}} \right.$
$\left \{ {{(5-x)(5+x) } \geq 0} \atop {9- x^{2} \ \textgreater \ 0}} \right.$
$\left \{ {{(5-x)(5+x) } \geq 0} \atop {(3- x)(3+x) \ \textgreater \ 0}} \right.$

--------[-5]--------+----------[5]------------
////////////////////////
-------------(-3)---+----(3)-----------------
////////////////

Ответ: $(-3;3)$