5/6 : 7 1/3=1,6:х Решите пропорцию! 3/14х-0,59=8\21х - 1,24 Решите...

1) $\frac{5}{6} : 7 \frac{1}{3}=1.6:x \\ \frac{5}{6} : \frac{22}{3}=\frac{16}{10x}\\ \frac{5}{6} \cdot \frac{3}{22}=\frac{16}{10x}\\ \frac{5}{44}=\frac{16}{10x}\\ 50x=16 \cdot 44\\ x= \frac{16 \cdot 44}{50}\\ x=14.08$

2) $\frac{3}{14x}-0,59=\frac{8}{21x} - 1,24 \\ \frac{3}{14x}- \frac{59}{100}=\frac{8}{21x} - \frac{124}{100}\\ \frac{3}{14x} -\frac{8}{21x}}=\frac{59}{100}-\frac{124}{100}\\ \frac{9}{42x}-\frac{16}{42x}=-\frac{65}{100}\\ \frac{7}{42x}=\frac{65}{100}\\ 65 \cdot 42x=700\\ x= \frac{700}{65 \cdot 42}\\ x=\frac{700}{2730}\\ x=\frac{70}{273}\\ x=\frac{10}{39}$

$14-\frac{13,2}{(3 \frac{11}{21}-2 \frac{4}{15})};\\ 1) \ 3 \frac{11}{21}-2 \frac{4}{15}=3\frac{55}{105}-2\frac{28}{105}=1\frac{27}{105}=1\frac{9}{35}\\ 2) \ \frac{132}{100}:\frac{44}{35}=\frac{132}{100} \cdot \frac{35}{44}=\frac{3}{20} \cdot \frac{7}{1}=\frac{21}{20}\\ 3) \ 14- \frac{21}{20}=14-1.05=12.95$