Решите систему уравнений методом подстановки x-2y =3 x+y= 4

Решите задачу:

$\left \{ {{x-2y =3} \atop {x+y= 4}} \right. \ \ \textless \ =\ \textgreater \ \ \left \{ {{4-y-2y=3} \atop {x=4-y}} \right. \ \ \textless \ =\ \textgreater \ \ \left \{ {{3y=1} \atop {x=4-y}} \right. \ \ \textless \ =\ \textgreater \ \ \left \{ {{y= \frac{1}{3} } \atop {x=4- \frac{1}{3} = \frac{11}{3} }} \right. \\ \\ OTBET: \ ( \frac{11}{3}; \ \frac{1}{3} )$