6y-20\\
16-y^2+y^2+5y-6y+20>0\\
-y+36>0\\
-y>-36\\
y<36" alt="1) (x+5)(x-5)-(x+3)x \leq x+1\\
x^{2} -25- x^{2} -3x-x-1 \leq 0\\
-4x-26 \leq 0\\
-4x \leq 26\\
x \geq - 6,5\\
2) (y+4)(4-y) +(y+5)y>6y-20\\
16-y^2+y^2+5y-6y+20>0\\
-y+36>0\\
-y>-36\\
y<36" align="absmiddle" class="latex-formula">