//Dev-C++ 5.11
#include
int main(void)
{float a[10][10]={0},newar[100]={0},min=2147483647;
int i,j,n,c,coucurr=1,newn=0,boo=0;
scanf("%d",&n);
for(i=0;i for(j=0;j {scanf("%f",&a[i][j]);
newar[newn]=a[i][j];
newn++;}
for(i=0;i {for(j=0;j if (newar[i]==newar[j] && i!=j)
coucurr++;
if (coucurr>1 && min>newar[i])
{min=newar[i]; boo=1;}
coucurr=1;}
if(boo)
printf("%f",min);
else
printf("Nothing");
return 0;}
Пример ввода:
3
1
2
2
3
3
3
4
4
4
Пример вывода:
2