Log1/3 x/9×log1/3 x/9+log1/3 x/3×log1/3 x/3=
=(log1/3x+log1/3 1/9)^2+(log1/3x+ log1/3 1/3)^2=
=(log1/3x+2)^2+(log1/3+1)^2=log^2 1/3x+4log1/3x+4+log^2 1/3x+2log1/3x+1=2log^2 1/3x+6log1/3x+5=1
log^2 1/3x+3log1/3x+2=0
обозначим log1/3x через у
у^2+3у+2=0
у1=-1
у2=-2
Отсюда :
х1=3
х2=9
Произведение корней равно =3×9=27