Очень нужно решить!!! Никак не могу.

Решите задачу:

$\frac{48p^3q^4}{36p^2q^3} = \frac{4pq}{3} \\\\ \frac{x^2+6x+9}{x^2-9} = \frac{(x+3)^2}{(x-3)(x+3)} = \frac{x+3}{x-3}$

$\frac{10x^2}{9y^2} = \frac{40x^3}{36xy^2} \\\ \frac{8}{12xy} =\frac{24y}{36xy^2} \\\\ \frac{b+2}{4b} = \frac{b^2-4}{4b(b-2)} \\\ \frac{4b+5}{4b-8} = \frac{4b^2+5b}{4b(b-2)} \\\\ \frac{2c}{c+d} = \frac{2c(d-c)}{d^2-c^2} \\\ \frac{3d}{d-c} = \frac{3d(d+c)}{d^2-c^2} \\\\ \frac{5t}{t^2-25} = \frac{5t(t-5)}{(t-5)^2(t+5)} \\\ \frac{t+5}{(t-5)^2}= \frac{(t+5)^2}{(t-5)^2(t+5)}$