СРОЧНО,ЖИЗНЬ ИЛИ ДВОЙКА,решите неравенства :(х-2)(х-3)>х^2(2х-1)(3х+5)≤6х^2

1)
$(x-2)(x-3)\ \textgreater \ x^2$

$x^2-3x-2x+6\ \textgreater \ x^2$

$x^2-5x+6-x^2\ \textgreater \ 0$

$-5x+6\ \textgreater \ 0$

$-5x\ \textgreater \ -6$

$x\ \textless \ 1.2$

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$x$ ∈ $(-$ ∞ $;1.2)$

2)
$(2x-1)(3x+5) \leq 6x^2$

$6x^2+10x-3x-5 \leq 6x^2$

$6x^2+7x-5-6x^2 \leq 0$

$7x-5 \leq 0$

$7x \leq 5$

$x \leq \frac{5}{7}$

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$x$ ∈ $(-$ ∞ $; \frac{5}{7} ]$