Упростите выражение (1) 5а²/2а³3а¹¹ (2) с⁴с¹⁴/10с^9 (3) (-3х²у^5)⁴/54х^6у^17

Решите задачу:

$\frac{5a^2}{2a^33a^{11}}=\frac{5a^2}{6a^{14}}=\frac{5}{6a^{12}} =\frac{5}{6}a^{-12}\\\\\\ \frac{c^4c^{14}}{10c^9}=\frac{c^{18}}{10c^9}=\frac{c^9}{10}=0,1c^9\\\\\\ \frac{(-3x^2y^5)^4}{54x^6y^{17}}=\frac{3^4x^8y^{20}}{3^3\cdot 2\cdot x^6y^{17}}=\frac{3x^2y^3}{2} =\frac{3}{2}x^2y^3$