Решите уравнение рациональным...

1)
$5 + \frac{3x-8}{2} + \frac{6 - x}{3} =-4 \\ \\ 5 + \frac{3}{2} x - 4 + 2 - \frac{1}{3}x = -4 \\ \\ \frac{9-2}{6} x +3 = -4 \\ \\ \frac{7}{6} x = -7 \\ \\ x = -7 * \frac{6}{7} = -6$

2)
$\frac{4x+ 12}{3} + \frac{25 - 8x}{5} =1 \\ \\ \frac{4}{3} x + 4 +5- \frac{8}{5} x=1 \\ \\ \frac{20-24}{15}x +9=1 \\ \\ - \frac{4}{15}x =-8 \\ \\ x= -8*(-\frac{15}{4} )=30$

3)
$\frac{3x-5}{5} + \frac{18 + x}{6} =25 \\ \\ \frac{3}{5} x - 1+3+ \frac{1}{6} x=25 \\ \\ \frac{18+5}{30} x+2=25 \\ \\ \frac{23}{30} x=23 \\ \\ x=23* \frac{30}{23} =30$

4)
$\frac{5x-8}{5} + \frac{4x+25}{4} = \frac{1}{4} \\ \\ x- \frac{8}{5} +x+ \frac{25}{4} = \frac{1}{4}$
2x - 1,6 + 6,25 = 0,25
2x = - 4,4
x = -2,2