1)√х+2=4 2)√x^2-28=6 3)3^√3-x^2=-1 4)4^√x^3-11=2 Помогите решить уравнения.

1) $\sqrt{x+2} = 4$

x+2 = 16

x = 14

2) $\sqrt{x^2 - 28} = 6$

x² - 28 = 36

x² = 36+28 = 64

x = 8

3) $3^ \sqrt{3-x^2}$ = 1

3⁰ = 1

3-х² = 0

х² = 3

х = $\sqrt{3}$

4) $4^ \sqrt{x^3-11}$ = 2

2 = $4 ^{ \frac{1}{2} }$

$\sqrt{x^3 - 11} = \frac{1}{2}$

x³ -11 = $\frac{1}{4}$

x³ = 11 $\frac{1}{4}$ = 11,25

х = $\sqrt[3]{11,25}$

Удачи!