X+2y+z=19
x^2+4y^2+z^2=133
xz=4y^2
x^2+2xz+z^2=133+4y^2
(x+z)^2=133+4y^2
x+z=19-2y
(19-2y)^2=133+4y^2
361-76y+4y^2=133+4y^2
76y=228
y=228/76=3
x+z=13
x^2-2xz+z^2=133-12*y^2=133-108=25
(x-z)^2=25
x+z=13
x-z=+-5
2x=13+-5
x1=9
x2=4
z1=4
z2=9
Ответ: (4;3;9) , (9;3;4)