Помогите решить уравнение Sin(-x) = 1
-sinx=1 -1(-sinx)=-1*1 sinx=-1 sinx=-1 sin(π-x)=-1 x=arcsin(-1) π-x=arcsin(-1) x=-π/2 π-x=-π/2 x=-π/2+2π, κ∈z π-x=-π/2+2π,κ∈z x=-π/2+2π,κ∈z x=3π/2-2κπ,κ∈z x=-π/2+2π,κ∈z x=3π/2+2κπ,k∈z