Помогите решить систему пожалуйста!

$\left \{ {{ \frac{x}{y} + \frac{y}{x} = \frac{25}{12} } \atop {x^2+y^2=25}} \right. \\ \left \{ {{ \frac{x^2+y^2}{xy} = \frac{25}{12} } \atop {x^2+y^2=25}} \right. \\ \left \{ {{xy = 12} \atop {x^2+y^2=25}} \right. \\ \left \{ {{y= \frac{12}{x} } \atop {x^2+ (\frac{12}{x})^2=25 }} \right.$

$x^2+ (\frac{12}{x})^2=25 \\ x^4-25x^2+144=0 \\ D = 625 - 576 = 49 \\ x^2= \frac{25-7}{2} =9 \\ x_1 = -3 \\ x_2 = 3 \\ x^2= \frac{25+7}{2} =16 \\ x_3=-4 \\ x_4 = 4$

$xy = 12 y_1 = -4\\ y_2 = 4\\ y_3 = -3\\ y_4 = 3$

Ответ: (-4; -3), (-3; -4), (3; 4), (4; 3)