1
ОДЗ
x+2>0⇒x>-2
x>0
2x+1>0⇒x>-0,5
x∈(0;∞)
log(3)[x(x+2)]x²+2x<2x+1<br>x²-1<0<br>(x-1)(x+1)<0<br>x=1 x=-4
-1x⇒(0;1)
2
ОДЗ
49-x²≥0
(7-x)(7+x)≥0
x=7 x=-7
-7≤x≤7
x>0
x∈(0;7]
√(49-x²)≥0⇒log(5)x/(x-5)≥0
1)log(5)x≥0⇒x≥1
x-5>0⇒x>5
52)log(5)x≤0⇒x≤1
x-5<0⇒x<5<br>0x∈(0;1] U (5;7]