((x-(9/x))-6)^2=(x-(9/x))-4Производим заменуt=x-(9/x)(t-6)^2=(t-4)t^2-13t+40=0D=b^2-4ac=9t1,2=(-b±sqrt(D))/2a=(13±3)/2t1=5t2=8 1) t1=5 x-(9/x)=5 x^2-5x-9=0 D=b^2-4ac=61 x1,2=(-b±sqrt(D))/2a=(5±sqrt(61))/2 x1=(5-sqrt(61))/2 x2=(5+sqrt(61)/2 2) t2=8 x-(9/x)=8 x^2-8x-9=0 D=b^2-4ac=100 x3,4=(-b±sqrt(D))/2a=(8±10)/2 x3=-1 x4=9 Ответ: x1=(5-sqrt(61))/2 x2=(5+sqrt(61)/2 x3=-1 x4=9