35 баллов Помогите решить номер 1132

Решите задачу:

$( \frac{9}{24}+\frac{2}{24}+\frac{20}{24} ):(\frac{2}{24}+\frac{8}{24}+\frac{20}{24})= \frac{31}{24}: \frac{30}{24} = \frac{31}{24}* \frac{24}{30}= \frac{31}{30}$

$( \frac{24}{36}-\frac{6}{36}-\frac{16}{36} ):(\frac{28}{36}-\frac{15}{36}-\frac{10}{36})= \frac{2}{36}: \frac{3}{36}= \frac{2}{3}$

$( \frac{9}{4}*\frac{4}{3}*\frac{8}{9} ):(\frac{6}{5}*\frac{4}{9}*\frac{5}{2})=2$