(2х-1)*(2х+1)-(2х+3)^2=38 помогите

Question

(2х-1)*(2х+1)-(2х+3)^2=38 помогите

Answer 1

( 2x - 1) * ( 2x + 1) - ( 2x + 3)^2 = 38
4 - 1 - 4 - 12x - 9 = 38
-1 - 12x - 9 = 38
-12x = 48 | : (-12)
X = -4

Answer 2

(2х-1)*(2х+1)-(2х+3)²=38
4х²-1-4х²-12х-9=38
-10-12х=38
-12х=38+10
-12х=48
х=-4